Testdome Java Questions And Answers Jun 2026

// Given a list of permissions (READ, WRITE, DELETE), return true if user can perform action enum Permission READ, WRITE, DELETE class User Set<Permission> permissions; public boolean can(Permission p) ...

public class TwoSum { public static int[] findTwoSum(int[] nums, int target) { Map<Integer, Integer> map = new HashMap<>(); for (int i = 0; i < nums.length; i++) int complement = target - nums[i]; if (map.containsKey(complement)) return new int[] map.get(complement), i ;

Automated tests run against large datasets. A nested loop ( testdome java questions and answers

class Animal public void makeSound() System.out.println("Some sound");

while (i<a.length) res[k++]=a[i++]; while (j<b.length) res[k++]=b[j++]; return res; // Given a list of permissions (READ, WRITE,

: Override the add(char c) method in the subclass to include a Character.isDigit(c) check before calling super.add(c) .

TestDome typically shows you 2 or 3 basic testing inputs. However, your score relies on hidden test cases. Before submitting, manually run through edge cases: empty strings, negative numbers, null values, and massive arrays. TestDome typically shows you 2 or 3 basic testing inputs

TestDome evaluates practical coding skills rather than rote memorization. You will generally encounter two types of questions:

import java.util.HashSet; import java.util.Set; import java.util.Arrays; public class MergeNames public static String[] uniqueNames(String[] names1, String[] names2) Set uniqueSet = new HashSet<>(); uniqueSet.addAll(Arrays.asList(names1)); uniqueSet.addAll(Arrays.asList(names2)); return uniqueSet.toArray(new String[0]); public static void main(String[] args) String[] names1 = new String[] "Ava", "Emma", "Olivia"; String[] names2 = new String[] "Olivia", "Sophia", "Emma"; // Expected output: Ava, Emma, Olivia, Sophia (order may vary) System.out.println(String.join(", ", uniqueNames(names1, names2))); Use code with caution. Explanation : Using a HashSet allows for

It avoids recursion stack overflow risks on deep trees by using an iterative approach, maintaining a time complexity and space complexity. 2. The "Two Sum" Optimization Problem

Many tasks have specific edge cases (like null inputs or empty arrays) that you must handle to get 100%.